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11p=-12+5p^2
We move all terms to the left:
11p-(-12+5p^2)=0
We get rid of parentheses
-5p^2+11p+12=0
a = -5; b = 11; c = +12;
Δ = b2-4ac
Δ = 112-4·(-5)·12
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*-5}=\frac{-30}{-10} =+3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*-5}=\frac{8}{-10} =-4/5 $
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